How do you solve #4x^2+32=0#? Precalculus Complex Zeros Complex Zeros on a Graphing Calculator 1 Answer MeneerNask Oct 5, 2016 First simplification is by dividing by #4# Explanation: #x^2+8=0->x^2=-8-># #x=+-sqrt(-8)=+-sqrt((-1)*8)-># #x=+-sqrt(-1)*sqrt8=+-isqrt8# Answer link Related questions How do I use a graphing calculator to find the complex zeros of #x^3-1#? How do I use a graphing calculator to find the complex zeros of #x^4-1?# How do I use a graphing calculator to find the complex zeros of #f(x)=x^3-4x^2+25x-100#? How do I use a graphing calculator to find the roots of the polynomial equation #x^3-4x^2+x+26=0#? How do I use a graphing calculator to find the roots of the polynomial equation... How do I use a graphing calculator to solve #x^2-5x-14=0#? How do I use a graphing calculator to solve #2x^2+2x=7x-2#? What does a complex zero look like on a graph? How do you solve #2x^2+18=0#? How do you solve #-5x^2-25=0#? See all questions in Complex Zeros on a Graphing Calculator Impact of this question 5533 views around the world You can reuse this answer Creative Commons License