# How do you solve 4x^2+32=0?

First simplification is by dividing by $4$
${x}^{2} + 8 = 0 \to {x}^{2} = - 8 \to$
$x = \pm \sqrt{- 8} = \pm \sqrt{\left(- 1\right) \cdot 8} \to$
$x = \pm \sqrt{- 1} \cdot \sqrt{8} = \pm i \sqrt{8}$