How do you solve #2x^2 - 250x + 5000 = 0#?

2 Answers
Mar 31, 2018

Answer:

25,100

Explanation:

#2x^2-250x+5000=0#
#rArr 2(x^2-125x+2500)=0#
#rArr x^2-125x+2500=0#
#rArr x^2-25x-100x+2500=0#
#rArr x(x-25)-100(x-25)=0#
#rArr (x-25)(x-100)=0#
#rArr (x-25)=0,(x-100)=0#
#rArr x = 25 & 100#

Mar 31, 2018

Answer:

#x=25" or "x=100#

Explanation:

#"take out a "color(blue)"common factor "2#

#rArr2(x^2-125x+2500)=0#

#"the factors of + 2500 which sum to - 125 are - 25 and - 100"#

#rArr2(x-25)(x-100)=0#

#"equate each factor to zero and solve for x"#

#x-25=0rArrx=25#

#x-100=0rArrx=100#