How do you solve #2x^2 – 2x – 3 = 0# by completing the square?

1 Answer
Apr 23, 2016

Answer:

#x=1/2+sqrt7/2# and
#x=1/2-sqrt7/2#

Explanation:

In #2x^2-2x-3=0#, let us first divide this by #2# and we get #x^2-x-3/2=0#. As the coefficient of #x# is #-1#, let us add and subtract #(-1)^2/4# or #1/4#, which gives us

#x^2-x+1/4-3/2-1/4=0# or

#(x-1/2)^2-7/4=0# or

#(x-1/2)^2-(sqrt7/2)^2=0# or

#(x-1/2-sqrt7/2)(x-1/2+sqrt7/2)=0# or

#x=1/2+-sqrt7/2#