# How do you solve 2x^2 = 32?

Jan 18, 2016

$x = 4 \mathmr{and} x = - 4$

#### Explanation:

First divide throughout by $2$ to get

${x}^{2} = 16$

Now take the square root on both sides to get

$x = \pm 4$.

You may now substitute the values of $x = 4 \mathmr{and} x = - 4$ back into the original equation and check that it satisfies the equation which it does.