How do you solve $2x^2 = 32$ ?

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Answer 1 · 2016-01-18T13:29:03

$x=4 or x=-4$

First divide throughout by $2$ to get

$x^2=16$

Now take the square root on both sides to get

$x=+-4$ .

You may now substitute the values of $x=4 and x=-4$ back into the original equation and check that it satisfies the equation which it does.

How do you solve 2x^2 = 322x^2 = 32?