Question

How do you solve `2x^2 -3x= -10` using the quadratic formula?

Answer 1

`x=(3+- sqrt71i)/4`

Explanation:

`2x^2-3x=-10`
`=>2x^2-3x+10=0`
`a=2`, `b=-3` and `c=10`
Quadratic formula is
`x=(-b+-sqrt(b^2-4ac))/(2a)`
Putting values of 'a', 'b' and 'c' in above formula
`x=(-(-3)+-(sqrt((-3)^2-4(2)(10))))/(2(2))`
`x=(3+-sqrt(9-80))/4`
`x=(3+-sqrt(-71))/4`

`x=(3+- sqrt71i)/4`