# How do you solve 2x^2 -3x= -10 using the quadratic formula?

Apr 7, 2016

$x = \frac{3 \pm \sqrt{71} i}{4}$

#### Explanation:

$2 {x}^{2} - 3 x = - 10$
$\implies 2 {x}^{2} - 3 x + 10 = 0$
$a = 2$, $b = - 3$ and $c = 10$
$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$
$x = \frac{- \left(- 3\right) \pm \left(\sqrt{{\left(- 3\right)}^{2} - 4 \left(2\right) \left(10\right)}\right)}{2 \left(2\right)}$
$x = \frac{3 \pm \sqrt{9 - 80}}{4}$
$x = \frac{3 \pm \sqrt{- 71}}{4}$
$x = \frac{3 \pm \sqrt{71} i}{4}$