# How do you solve #2x^2-3x=-4# using the quadratic formula?

##### 1 Answer

Jul 21, 2016

No real roots

#### Explanation:

Use the new improved quadratic formula (Socratic Search)

y = 2x^2 - 3x + 4 = 0

D = d^2 = b^2 - 4ac = 9 - 32 = - 23.

Because D < 0, there are no real roots. There are 2 complex roots.