How do you solve #2x^2+5x-12=0#?
Solve it by the new Transforming Method (Socratic Search).
Proceeding. Find the 2 real roots of y', then, divide them by a = 2.
Find 2 real roots knowing the sum (-b = -5) and the product
(ac = -24).
They are 3, and -8.
The 2 real roots of y are:
Note . This method avoids the lengthy factoring by grouping and solving the 2 binomials.