# How do you solve 2x^2-9x-35=0?

Sep 1, 2016

$x = - \frac{5}{2} \mathmr{and} 7$

#### Explanation:

Solve by factoring.

$2 {x}^{2} - 9 x - 35 = 0$

Find two numbers that multiply to $2 \times - 35 = - 70$ and that add to $- 9$. Two numbers that do this are $- 14 \mathmr{and} 5$.

$2 {x}^{2} - 14 x + 5 x - 35 = 0$

$2 x \left(x - 7\right) + 5 \left(x - 7\right) = 0$

$\left(2 x + 5\right) \left(x - 7\right) = 0$

$x = - \frac{5}{2} \mathmr{and} 7$

Hopefully this helps!