# How do you solve 2x+3<=-4 or 2x+3>=4?

Dec 24, 2017

$x \le - \frac{7}{2}$ or $x \ge \frac{1}{2}$.

#### Explanation:

Solve each individually.

$2 x + 3 \le - 4$
$2 x \le - 7$
$x \le - \frac{7}{2}$

$2 x + 3 \ge 4$
$2 x \ge 1$
$x \ge \frac{1}{2}$

So the answer is $x \le - \frac{7}{2}$ or $x \ge \frac{1}{2}$.