# How do you solve 2x+3>7 or 2x+9>11?

##### 1 Answer

#### Answer:

The solution set is

#### Explanation:

For each of these inequalities, there will be a set of

Since we're asked to solve a "this OR that" pair of inequalities, what we'd like to know are *all the #x#-values that will work for at least one of them.* To do this, we solve both inequalities for

**Inequality 1:**

#2x+3>7" "=>" "2x>4" "# (subtract 3 from both sides)

#color(white)(2x+3>7)" "=>" "x>2" "# (divide both sides by 2)

**Inequality 2:**

#2x+9>11" "=>" "2x>2" "# (subtract 9 from both sides)

#color(white)(2x+9>11)" "=>" "x>1" "# (divide both sides by 2)

So we need to list all the *either* *or*

In this case, if an *subset* of the one for

The solution set we need is simply "all

#{x | x>1}#

or

#x in (1, oo)#