How do you solve #2x^3-8x=0# by factoring?

1 Answer
Oct 6, 2015

Answer:

#x=0color(white)(XXX")# or
#x=-2color(white)("XX")# or
#x=+2#

Explanation:

#2x^3-8x=0#

#rarrcolor(white)("XXX")(2)(x)(x^2-4)=0#

#rarrcolor(white)("XXX")(2)(x)(x+2)(x-2)=0#

#rarrcolor(white)("XXX")x=0color(white)("XX")or color(white)("XX")x+2=0color(white)("XXX")orcolor(white)("XX")x-2=0#

#rarrcolor(white)("XXX")x=0color(white)("XX")orcolor(white)("XX")x=-2color(white)("XXXX")orcolor(white)("XX")x=+2#