How do you solve #2x-3<x+4<3x-2#?

1 Answer
May 9, 2018

Answer:

Isolate for x on both sides

Explanation:

I like to tackle them separately, so I get:

1. #2x-3 < x+4#
2. #x+4 < 3x-2#

Lets try to solve them by isolating for "x". but keep in mind we want our "x" term in the middle at the end so we will isolate "x" to the right side for 1 and to the left for 2

1.
#-3-4 < x-2x#
#-7<-x#
#7>x# note: Sign switched because we divide by a negative number.

2.
#x+4<3x-2#
#x-3x<-2-4#
#-2x<-6#
#x>3# note: Sign switched because we divide by a negative number.

So our final is...

#7>x>3#
or
#3< x < 7#