How do you solve #2x-5<x+1#?

1 Answer
May 11, 2015

You can solve it as a normal equation isolating #x# on one side (changing signs when necessary) and "reading", at the end, the result:
#2x-x<5+1#
#x<6#
This tells you that for the first equation to be smaller than the second you cal only choose values of #x# which are #<6#.
If you try, for example, #x=7# (which is bigger than #6#) you get:
#2*7-5<7+1#
#9<8# which is not true!
Instead if you try, for example, #x=5# (which is smaller than #6#) you get:
#2*5-5<5+1#
#5<6# which is true!

Hope it helps!