# How do you solve 2x² - 5x - 12 = 0?

Jun 23, 2015

I found:
${x}_{1} = 4$
${x}_{2} = - \frac{6}{4} = - \frac{3}{2}$

#### Explanation:

You can use the Quadratic Formula:
${x}_{1 , 2} = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$
Your equation can be written in the general form:
$a {x}^{2} + b x + c = 0$
Where:
$a = 2$
$b = - 5$
$c = - 12$
So using these values in the Quadratic Formula you get:
${x}_{1 , 2} = \frac{5 \pm \sqrt{25 + 96}}{4} = \frac{5 \pm 11}{4} =$
${x}_{1} = 4$
${x}_{2} = - \frac{6}{4} = - \frac{3}{2}$