# How do you solve (2y+6)(y-1)=0?

Jun 2, 2017

$y = - 3$ and $y = 1$

#### Explanation:

Set each factor equal to $0$ and solve for $y$.

1st Factor:

$2 y + 6 = 0$

$2 y = - 6$

$y = - \frac{6}{2} = - 3$

2nd Factor

$y - 1 = 0$

$y = 1$

Jun 2, 2017

See a solution process below:

#### Explanation:

Using the zero product principle we solve this problem by equating each of the terms in parenthesis to $0$ and then solving for $y$:

Solution 1)

$2 y + 6 = 0$

$2 y + 6 - \textcolor{red}{6} = 0 - \textcolor{red}{6}$

$2 y + 0 = - 6$

$2 y = - 6$

$\frac{2 y}{\textcolor{red}{2}} = - \frac{6}{\textcolor{red}{2}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} y}{\cancel{\textcolor{red}{2}}} = - 3$

$y = - 3$

Solution 2)

$y - 1 = 0$

$y - 1 + \textcolor{red}{1} = 0 + \textcolor{red}{1}$

$y - 0 = 1$

$y = 1$

The solution is: $y = - 3$ and $y = 1$