How do you solve #3(2 − 2x) > -4x + 8#?

1 Answer
May 30, 2018

Answer:

#x< -1#

Explanation:

#"distribute the bracket on the left side of the inequality"#

#6-6x> -4x+8#

#"add "4x" to both sides"#

#6-2x> 8#

#"subtract 6 from both sides"#

#-2x> 2#

#"divide both sides by "-2#

#color(blue)"reversing the sign as a consequence"#

#x< -1" is the solution"#

#x in(-oo,-1)larrcolor(blue)"in interval notation"#