# How do you solve 3- 2( 5x - 4) > - 9 and 3x > - 4( x - 2)?

Mar 17, 2018

$3 - 2 \left(5 x - 4\right) > - 9$ ----------------- $3 x > - 4 \left(x - 2\right)$
$x < 2$ -----------------------------------$x > \frac{8}{7}$

#### Explanation:

Ok so the first one $3 - 2 \left(5 x - 4\right)$
First we distribute the $- 2$ giving us
$3 - 10 x + 8 > - 9$

We now combine like terms on the left side
$11 - 10 x > - 9$

Subtract 11 on both sides giving us
$- 10 x > - 20$

We now divide by $- 10$ on both sides.
REMEMBER: When dividing by a negative the sign always turn to the other side.

$\frac{- 10 x}{- 10} < - \frac{20}{- 10}$

$x < 2$

Ok now the second one.
First we distribute the $- 4$ giving us
$3 x > - 4 x + 8$

Now we add $4 x$ on both sides giving us
$7 x > 8$

Now we divide $7$ on both sides
$\frac{7 x}{7} > \frac{8}{7}$

$x > \frac{8}{7}$