How do you solve $-3-(2b-6) >=10$ ?

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Answer 1 · 2018-07-12T07:43:45

$b<=-7/2$

Solve:

$-3-(2b-6)>=10$

Simplify the parentheses.

$-3-2b+6>=10$

Simplify.

$-2b+3>=10$

Subtract $3$ from both sides.

$-2b>=10-3$

Simplify.

$-2b>=7$

Divide both sides by $-2$ . This will reverse the inequality.

$b<=-7/2$

How do you solve -3-(2b-6) >=10-3-(2b-6) >=10?