# How do you solve -3-(2b-6) >=10?

Jul 12, 2018

$b \le - \frac{7}{2}$

#### Explanation:

Solve:

$- 3 - \left(2 b - 6\right) \ge 10$

Simplify the parentheses.

$- 3 - 2 b + 6 \ge 10$

Simplify.

$- 2 b + 3 \ge 10$

Subtract $3$ from both sides.

$- 2 b \ge 10 - 3$

Simplify.

$- 2 b \ge 7$

Divide both sides by $- 2$. This will reverse the inequality.

$b \le - \frac{7}{2}$