# How do you solve 3/(2x + 5) <= 0?

Oct 1, 2015

$x < - \frac{5}{2}$

#### Explanation:

Note that $\frac{3}{2 x + 5}$ can not be equal to $0$ for any finite value of $x$.

For $\frac{3}{2 x + 5}$ to be $< 0$

$\textcolor{w h i t e}{\text{XXX}} 2 x + 5$ must be negative

That is
$\textcolor{w h i t e}{\text{XXXXX}} 2 x + 5 < 0$

$\rightarrow \textcolor{w h i t e}{\text{XXX}} x < - \frac{5}{2}$