Question

How do you solve `3^(2x+5)=27^x`?

Answer 1

`x=5`

Explanation:

Using laws of exponents we may write this equation as

`3^(2x)*3^5=3^(3x)`

`therefore3^5=3^(3x-2x)`

`therefore 3^5=3^x` and hence `x=5`