How do you solve #3(2x+7)=27# using the distributive property?

1 Answer
May 16, 2017

Answer:

#x=1#

Explanation:

#"distribute the bracket on the left side"#

#rArr6x+21=27#

#"subtract 21 from both sides"#

#6xcancel(+21)cancel(-21)=27-21#

#rArr6x=6#

#"divide both sides by 6"#

#(cancel(6) x)/cancel(6)=6/6#

#rArrx=1#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#3(2xx1+7)=3xx9=27=" right side"#

#rArrx=1" is the solution"#