How do you solve #3^ { 3r - 1} = 3^ { - 2r - 3}#?

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Jim G. Share
Apr 16, 2017

Answer:

#r=-2/5#

Explanation:

Since the #color(blue)"bases on both sides of the equation are 3"# we can equate the exponents.

#rArr3r-1=-2r-3#

#rArr5r=-2#

#rArrr=-2/5#

#color(blue)"As a check"#

#3^((-6/5-5/5))=3^(-11/5)#

#"and " 3^((4/5-15/5))=3^(-11/5)#

#rArrr=-2/5" is the solution"#

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Answer:

In the given eqn, the bases are equal, so equate powers on both sides.

Explanation:

#3r-1=-2r-3#

#5r=-2#

#r= -2/5#

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