How do you solve #3/4 x + 2>20#?

1 Answer
Apr 15, 2017

Answer:

See the entire solution process below:

Explanation:

First, subtract #color(red)(2)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#3/4x + 2 - color(red)(2) > 20 - color(red)(2)#

#3/4x + 0 > 18#

#3/4x > 18#

Now, multiply each side of the inequality by #color(red)(4)/color(blue)(3)# to solve for #x# while keeping the inequality balanced:

#color(red)(4)/color(blue)(3) xx 3/4x > color(red)(4)/color(blue)(3) xx 18#

#cancel(color(red)(4))/cancel(color(blue)(3)) xx color(blue)(cancel(color(black)(3)))/color(red)(cancel(color(black)(4)))x > color(red)(4)/cancel(color(blue)(3)) xx color(blue)(cancel(color(black)(18))) 6#

#x > 4 xx 6#

#x > 24#