# How do you solve 3/4 x + 2>20?

Apr 15, 2017

See the entire solution process below:

#### Explanation:

First, subtract $\textcolor{red}{2}$ from each side of the inequality to isolate the $x$ term while keeping the inequality balanced:

$\frac{3}{4} x + 2 - \textcolor{red}{2} > 20 - \textcolor{red}{2}$

$\frac{3}{4} x + 0 > 18$

$\frac{3}{4} x > 18$

Now, multiply each side of the inequality by $\frac{\textcolor{red}{4}}{\textcolor{b l u e}{3}}$ to solve for $x$ while keeping the inequality balanced:

$\frac{\textcolor{red}{4}}{\textcolor{b l u e}{3}} \times \frac{3}{4} x > \frac{\textcolor{red}{4}}{\textcolor{b l u e}{3}} \times 18$

$\frac{\cancel{\textcolor{red}{4}}}{\cancel{\textcolor{b l u e}{3}}} \times \frac{\textcolor{b l u e}{\cancel{\textcolor{b l a c k}{3}}}}{\textcolor{red}{\cancel{\textcolor{b l a c k}{4}}}} x > \frac{\textcolor{red}{4}}{\cancel{\textcolor{b l u e}{3}}} \times \textcolor{b l u e}{\cancel{\textcolor{b l a c k}{18}}} 6$

$x > 4 \times 6$

$x > 24$