How do you solve # 3/4x + 11 = 20#?

2 Answers
Feb 13, 2016

Answer:

#x= 12#

Explanation:

First, get all the numbers to one side and the variable, x, to the other by subtracting 11 from both sides.

#3/4x +11=20#
#3/4x= 9#

Multiple both sides of the reciprocal of the coefficient (the number in front of the variable) to get x. The reciprocal for a fraction can be obtained by flipping the denominator and the numerator. For example, the reciprocal of the fraction #2/5# is #5/2#.

In this case, the coefficient is #3/4#, so its reciprocal would be #4/3#. Multiple both sides by #4/3# to cancel out the coefficient and find the value of x.

#(4/3)(3/4)x= 9(4/3)#

#x=12#

Feb 14, 2016

Answer:

#x=12#

Explanation:

#3/4 x+11=20#

Subtract both sides by #11#:

#3/4 x=20-11#

#3/4 x=9#

Divide both sides by #3/4#

#x=9-:3/4#

#x=9*4/3#

#x=cancel9*4/cancel3#

#x=3*4=12#