# How do you solve  (3/5)x ≤ 10 + (1/5)x?

May 5, 2015

The answer is $x \le 25$ .

Solve $\frac{3}{5} x \le 10 + \frac{1}{5} x$ as if there was an equal sign between the two sides instead of an inequality.

Subtract $\frac{1}{5} x$ from both sides to get $x$ on one side.

$\frac{2}{5} x \le 10$

Multiply both sides by $\frac{5}{2}$ to cancel $\frac{2}{5}$. (This is the same as dividing by $\frac{2}{5}$ .)

$\frac{\cancel{2}}{\cancel{5}} x \cdot \frac{\cancel{5}}{\cancel{2}} \le 10 \cdot \frac{5}{2}$ =

$x \le \frac{50}{2}$ =

$x \le 25$