How do you solve $3 (5 x - 4) < 4 (3 x - 2)$ $3(5x-4)<4(3x-2)$ ?

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Answer 1 · 2018-04-22T13:47:58

$x < \frac{4}{3}$ $x<4/3$

$3 (5 x - 4) < 4 (3 x - 2)$ $3(5x-4)<4(3x-2)$

Expand brackets:

$15 x - 12 < 12 x - 8$ $15x-12<12x-8$

Take away $12 x$ $12x$ from both sides:

$3 x - 12 < - 8$ $3x-12<-8$

Add 12 to both sides:

$3 x < 4$ $3x<4$

Simplify:

$x < \frac{4}{3}$ $x<4/3$

How do you solve 3(5x−4)<4(3x−2)3(5x-4)<4(3x-2)?