How do you solve | 3( x + 2) - 4 | = 1?

Sep 1, 2016

$x = - \frac{1}{3} \mathmr{and} - 1$

Explanation:

Start by distributing within the absolute value.

$| 3 x + 6 - 4 | = 1$

$| 3 x + 2 | = 1$

Case 1: The absolute value is positive

$3 x + 2 = 1$

$3 x = - 1$

$x = - \frac{1}{3}$

Case 2: The absolute value is negative

$- \left(3 x + 2\right) = 1$

$- 3 x - 2 = 1$

$- 3 x = 3$

$x = - 1$

Hopefully this helps!