# How do you solve 3(x + 2) >x?

Apr 17, 2018

$x > - 3$
$3 \left(x + 2\right) > x$
$3 x + 6 > x$
$2 x + 6 > 0$
$2 x > - 6$
$x > - \frac{6}{2}$
$x > - 3$