# How do you solve 30< 5x \leq 40?

Jan 26, 2017

See the entire solution process below:

#### Explanation:

To solve this divide each portion of the system of inequalities by $\textcolor{red}{5}$ to solve for $x$ while keeping the system of inequalities balanced:

$\frac{30}{\textcolor{red}{5}} < \frac{5 x}{\textcolor{red}{5}} \le \frac{40}{\textcolor{red}{5}}$

$6 < \frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{5}}} x}{\cancel{\textcolor{red}{5}}} \le 8$

$6 < x \le 8$