# How do you solve 32-5n>7-5(n-5)?

Holds for all $n \setminus \in \setminus m a t h \boldsymbol{R}$

#### Explanation:

$32 - 5 n > 7 - 5 \left(n - 5\right)$

$32 - 5 n > 7 - 5 n + 25$

$32 - 5 n > 32 - 5 n$

$32 - 5 n + 5 n > 32 - 5 n + 5 n$

$32 > 32$

Above inequality is true for all $n \setminus \in R$