Question

How do you solve `33x^2=-22x`?

Answer 1

`x=0, or x =-2/3`
See below.

Explanation:

`33x^2=-22x`

`33x^2+22x=0`

`11x(3x+2)=0`

So, setting each factor equal to `0` gives:

`x=0, or x =-2/3`