How do you solve #36 = 4 sqrt(4m^2+5)#?

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Answer 1 · 2018-03-25T07:07:53

The two solutions are #m=+-sqrt19#.

#36=4sqrt(4m^2+5)#

#color(blue)(color(black)36/4)=color(blue)(color(black)(4sqrt(4m^2+5))/4)#

#color(blue)(color(black)36/4)=color(blue)(color(black)(color(red)cancelcolor(Black)4sqrt(4m^2+5))/color(red)cancelcolor(black)4)#

#color(blue)(color(black)36/4)=sqrt(4m^2+5)#

#9=sqrt(4m^2+5)#

#9^2=(sqrt(4m^2+5))^2#

#9^2=4m^2+5#

#81=4m^2+5#

#76=4m^2#

#color(blue)(color(black)76/4)=color(blue)(color(black)(4m^2)/4)#

#color(blue)(color(black)76/4)=color(blue)(color(black)(color(red)cancelcolor(black)4m^2)/color(red)cancelcolor(black)4)#

#19=m^2#

#+-sqrt19=sqrt(m^2)#

#m=+-sqrt19#

These are the solutions. Hope this helped!