How do you solve #36 = 4 sqrt(4m^2+5)#?

1 Answer
Mar 25, 2018

Answer:

The two solutions are #m=+-sqrt19#.

Explanation:

#36=4sqrt(4m^2+5)#

#color(blue)(color(black)36/4)=color(blue)(color(black)(4sqrt(4m^2+5))/4)#

#color(blue)(color(black)36/4)=color(blue)(color(black)(color(red)cancelcolor(Black)4sqrt(4m^2+5))/color(red)cancelcolor(black)4)#

#color(blue)(color(black)36/4)=sqrt(4m^2+5)#

#9=sqrt(4m^2+5)#

#9^2=(sqrt(4m^2+5))^2#

#9^2=4m^2+5#

#81=4m^2+5#

#76=4m^2#

#color(blue)(color(black)76/4)=color(blue)(color(black)(4m^2)/4)#

#color(blue)(color(black)76/4)=color(blue)(color(black)(color(red)cancelcolor(black)4m^2)/color(red)cancelcolor(black)4)#

#19=m^2#

#+-sqrt19=sqrt(m^2)#

#m=+-sqrt19#

These are the solutions. Hope this helped!