# How do you solve 3b(9b-27)=0?

Apr 18, 2017

See the entire solution process below:

#### Explanation:

We need to solve each term for $0$ to determine the complete solution of the problem:

Solution 1)

$3 b = 0$

$\frac{3 b}{\textcolor{red}{3}} = \frac{0}{\textcolor{red}{3}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}} b}{\cancel{\textcolor{red}{3}}} = 0$

$b = 0$

Solution 2)

$9 b - 27 = 0$

$9 b - 27 + \textcolor{red}{27} = 0 + \textcolor{red}{27}$

$9 b - 0 = 27$

$9 b = 27$

$\frac{9 b}{\textcolor{red}{9}} = \frac{27}{\textcolor{red}{9}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{9}}} b}{\cancel{\textcolor{red}{9}}} = 3$

$b = 3$

The solution is: $b = 0$ and $b = 3$