How do you solve #-3e^(7a+9)+6=-6#?

1 Answer
Shwetank Mauria
Oct 8, 2016

#3e^(7a+9)+6==-6# does not have any solution.

Explanation:

#3e^(7a+9)+6==-6#

#hArr3e^(7a+9)==-6-6=-12# and

#e^(7a+9)==-12/3=-4#

But no power of #e# can be negative, as for all #x's#, #e^x# is positive.
graph{e^x [-10, 10, -5, 5]}

Hence, #3e^(7a+9)+6==-6# does not have any solution.

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