# How do you solve 3k(k+10)=0?

Apr 10, 2018

$k = 0 , k = - 10$

#### Explanation:

Suppose you have a product $a \cdot b \cdot c = 0$. Then if any of $a , b$ or $c$ is equal to zero, the equation is true. This is because any number times zero is equal to zero. For example, if you have $a = 0$, then $0 \cdot b \cdot c = 0$, which is true. This is true for any number of terms in the product.

In your case, you have two terms in your product, $\left(3 k\right) \cdot \left(k + 10\right) = 0$. As per above, the equation is true when any of the terms are zero. We solve for this algebraically by setting each one to zero.

$3 k = 0 \to k = 0$

$k + 10 = 0 \to k = - 10$

These are the solutions to the problem.