# How do you solve 3n^2-14n=-16?

Apr 17, 2016

2 and $\frac{8}{3}$
$y = 3 {n}^{2} - 14 n + 16 = 0$
Transformed equation $y ' = {n}^{2} - 14 n + 48 = 0$
Back to y, the 2 real roots are: $\frac{6}{3} = 2$ and $\frac{8}{3}$