How do you solve #3n^2-14n=-16#?

1 Answer
Apr 17, 2016

Answer:

2 and #8/3#

Explanation:

#y = 3n^2 - 14n + 16 = 0#
Use the new Transforming Method (Google, Yahoo Search)
Transformed equation #y' = n^2 - 14n +48 = 0#
Factor pairs of (ac = 48) --> ...(4, 12)(6, 8). This sum is 14 = - b.
Then, the 2 real roots of y' are: 6 and 8.
Back to y, the 2 real roots are: #6/3 = 2# and #8/3#