How do you solve # 3sqrt(2x)=4# and find any extraneous solutions?

1 Answer
Jul 8, 2017

Answer:

See below.

Explanation:

#3sqrt(2x)=4#

#sqrt(2x)=4/3#

#2x=16/9#

#x=8/9#

There will be extraneous solutions ONLY if the equation equals a negative number, or if the number inside the radical is imaginary. Since this does not describe our equation, there are no extraneous solutions.