How do you solve $3 \sqrt{2 x} = 4$ $3sqrt(2x)=4$ and find any extraneous solutions?

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How do you solve $3 \sqrt{2 x} = 4$ $3sqrt(2x)=4$ and find any extraneous solutions?

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Answer 1 · 2017-07-08T19:45:53

See below.

Explanation:

$3 \sqrt{2 x} = 4$ $3sqrt(2x)=4$

$\sqrt{2 x} = \frac{4}{3}$ $sqrt(2x)=4/3$

$2 x = \frac{16}{9}$ $2x=16/9$

$x = \frac{8}{9}$ $x=8/9$

There will be extraneous solutions ONLY if the equation equals a negative number, or if the number inside the radical is imaginary. Since this does not describe our equation, there are no extraneous solutions.

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How do you solve $3 \sqrt{2 x} = 4$ $3sqrt(2x)=4$ and find any extraneous solutions?

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Science

Math

Humanities

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How do you solve 3√2x=4 3sqrt(2x)=4 and find any extraneous solutions?

1 Answer

Explanation:

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Impact of this question

How do you solve $3 \sqrt{2 x} = 4$ $3sqrt(2x)=4$ and find any extraneous solutions?