Question

How do you solve `-3x + 2 >11` or `5(x - 2) <0`?

Answer 1

Solution : `x < -3` , in interval notation : `(-oo, -3)`

Explanation:

1) `-3x +2 > 11 or -3x > 9 or -x > 3 or x < -3`

2) `5 (x-2) < 0 or x-2 < 0 or x < 2`

`x < -3` satisfies both inequaity.

Solution : `x < -3` , in interval notation : `(-oo, -3)` [Ans]