# How do you solve #3x^2+13x-10=0#?

##### 3 Answers

See a solution process below:

#### Explanation:

We can use the quadratic formula to solve this problem.

The quadratic formula states:

For

Substituting:

#### Explanation:

Use the new Transforming Method (Google Search):

Transformed equation:

Proceeding. Find 2 real roots of y', then. divide them by a = 3.

Find 2 real roots knowing the sum (-b = -13) and the product (ac = -30). They are: 2 and - 15.

Back to y, the 2 real roots are:

#### Explanation:

Given:

#3x^2+13x-10=0#

Use an AC method to factor the quadratic:

Look for a pair of factors of

The pair

Use this pair to split the middle term and factor by grouping:

#0 = 3x^2+13x-10#

#color(white)(0) = (3x^2+15x)-(2x+10)#

#color(white)(0) = 3x(x+5)-2(x+5)#

#color(white)(0) = (3x-2)(x+5)#

Hence zeros:

#x=2/3" "# and#" "x=-5#