# How do you solve -3x^2+26x=16?

Feb 13, 2017

The roots of the quadratic are 0.67 and 8

#### Explanation:

Start by rearranging the equation into the standard form

$- 3 {x}^{2} + 26 x - 16 = 0$

Using the quadratic formula $\frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

substitute in the values from the equation
$\frac{- 26 \pm \sqrt{{26}^{2} - 4 \cdot - 3 \cdot - 16}}{2 \cdot - 3}$

Simplifying
$\frac{- 26 \pm \sqrt{676 - 192}}{-} 6$

$\frac{- 26 \pm 22}{-} 6$

Using the positive discriminant (+22) the root is 0.67
Using the negative discriminant (-22), the root is 8