# How do you solve 3x^2 - 2x - 2 = 0 by completing the square?

Jul 9, 2017

$x = \frac{1}{3} \pm \sqrt{\frac{7}{9}}$

#### Explanation:

$3 {x}^{2} - 2 x = 2$
Divide both sides by 3
${x}^{2} - \frac{2 x}{3} = \frac{2}{3}$
${x}^{2} - \frac{2 x}{3} + \frac{1}{9} = \frac{2}{3} + \frac{1}{9} = \frac{7}{9}$
${\left(x - \frac{1}{3}\right)}^{2} = \frac{7}{9}$
$x - \frac{1}{3} = \pm \sqrt{\frac{7}{9}}$
$x = \frac{1}{3} \pm \sqrt{\frac{7}{9}}$