Question

How do you solve `3x^2 - 2x - 2 = 0` by completing the square?

Answer 1

`x = 1/3 +- sqrt(7/9)`

Explanation:

`3x^2 - 2x = 2`
Divide both sides by 3
`x^2 - (2x)/3 = 2/3`
`x^2 - (2x)/3 + 1/9 = 2/3 + 1/9 = 7/9`
`(x - 1/3)^2 = 7/9`
`x - 1/3 = +- sqrt(7/9)`
`x = 1/3 +- sqrt(7/9)`