Question

How do you solve `3x^2+3x+1=0` using the quadratic formula?

Answer 1

No roots

Explanation:

`x=(-b\pmsqrt(b^2-4ac))/(2a)` is the formula and `a, b and c` are found from `ax^2+bx +c`.

So in the given equation `a=3, b=3 and c=1`

`=>` `x=(-3\pmsqrt(3^2-4xx3xx1))/(2xx3)`

`=>` `x=(-3\pmsqrt(-3))/6`

As you cannot take the square root of a negative number this means there is no solutions. This means the `u` shaped parabola is ABOVE the `x` axis.