# How do you solve 3x^2+3x+1=0 using the quadratic formula?

Apr 19, 2018

No roots

#### Explanation:

$x = \frac{- b \setminus \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$ is the formula and $a , b \mathmr{and} c$ are found from $a {x}^{2} + b x + c$.

So in the given equation $a = 3 , b = 3 \mathmr{and} c = 1$

$\implies$ $x = \frac{- 3 \setminus \pm \sqrt{{3}^{2} - 4 \times 3 \times 1}}{2 \times 3}$

$\implies$ $x = \frac{- 3 \setminus \pm \sqrt{- 3}}{6}$

As you cannot take the square root of a negative number this means there is no solutions. This means the $u$ shaped parabola is ABOVE the $x$ axis.