How do you solve #3x^2+3x+1=0# using the quadratic formula?

1 Answer
Apr 19, 2018

Answer:

No roots

Explanation:

#x=(-b\pmsqrt(b^2-4ac))/(2a)# is the formula and #a, b and c# are found from #ax^2+bx +c#.

So in the given equation #a=3, b=3 and c=1#

#=># #x=(-3\pmsqrt(3^2-4xx3xx1))/(2xx3)#

#=># #x=(-3\pmsqrt(-3))/6#

As you cannot take the square root of a negative number this means there is no solutions. This means the #u# shaped parabola is ABOVE the #x# axis.