How do you solve #3x + 2< 5( x - 4)#?

1 Answer
Apr 12, 2018

Answer:

#x > 11#

Explanation:

To just solve the equation for x, just do:

First, Distribute the #5(x-4)#
#5x-20#

Second, from #3x+2 < 5x-20#, add 20 to the other side of the '<' and then subtract 3x to the other side where -20 was. Therefore, you would have: #22 < 2x#.

Finally, simply divide 2 on each side of the equation and you would get: #11 < x# or #x > 11#.