# How do you solve 3x^2 + 7x - 6 = 0?

Jun 13, 2015

You get two solutions:
${x}_{1} = \frac{2}{3}$
${x}_{2} = - 3$

#### Explanation:

You can use the Quadratic Formula: ${x}_{1 , 2} = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$;
Your equation is in the form:
$a {x}^{2} + b x + c = 0$
Where:
$a = 3$
$b = 7$
$c = - 6$
so, using these values into the Quadratic Formula you get:
${x}_{1 , 2} = \frac{- 7 \pm \sqrt{49 + 72}}{6} = \frac{- 7 \pm 11}{6} =$
you get two solutions:
${x}_{1} = \frac{2}{3}$
${x}_{2} = - 3$