How do you solve -3x^2 - x + 2 = 0?

Jun 6, 2018

$x = - 1 , \frac{2}{3}$

Explanation:

$- 3 {x}^{2} - x + 2 = 0$

(−3x+2)(x+1) = 0

Solving for the first solution

$- 3 x + 2 = 0$

$- 3 x = - 2$

$x = \frac{2}{3}$

Solving for the second solution

$x + 1 = 0$

$x = - 1$