# How do you solve 3x+3<3 and -8x+6>=0?

Jul 9, 2015

$x < 0$

#### Explanation:

Simplify the inequalities:
$3 x + 3 < 3$ => $x < 0$
and
$- 8 x + 6 \ge 0$ => $x \le \frac{6}{8}$

Take a union of the in equalities we see the first equality is only true if the second is true (the second is therefore redundant).