How do you solve 3x+3<3 and $-8x+6>=0$ ?

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Answer 1 · 2015-07-09T12:44:07

$x<0$

Simplify the inequalities:
$3x+3<3$ => $x<0$
and
$-8x+6>=0$ => $x<=6/8$

Take a union of the in equalities we see the first equality is only true if the second is true (the second is therefore redundant).

How do you solve 3x+3<3 and -8x+6>=0-8x+6>=0?