How do you solve #3x^4+38=0#? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Alan P. Dec 12, 2016 #3x^4+38=0# has no Real solutions. Explanation: For all Real values of #x# #color(white)("XXX")x^2 >= 0# #color(white)("XXX")rarr x^4 >= 0# #color(white)("XXX")rarr 3x^4 >= 0# #color(white)("XXX")rarr 3x^4+38 > 0# Answer link Related questions How do I use DeMoivre's theorem to find #(1+i)^5#? How do I use DeMoivre's theorem to find #(1-i)^10#? How do I use DeMoivre's theorem to find #(2+2i)^6#? What is #i^2#? What is #i^3#? What is #i^4#? How do I find the value of a given power of #i#? How do I find the #n#th power of a complex number? How do I find the negative power of a complex number? Write the complex number #i^17# in standard form? See all questions in Powers of Complex Numbers Impact of this question 1310 views around the world You can reuse this answer Creative Commons License