How do you solve 3y²+14y=5?

1 Answer
Nghi N.
Mar 27, 2016

1/3 and -5

Explanation:

f(y) = 3y^2 + 14y = 5 = 0.
Use the new Transforming Method (Google, Yahoo Search).
Transformed equation: f'(y) = y^2 + 14y - 15.
Since a + b + c = 0, the 2 real roots of f'(y) are: ( 1) and (c/a = - 15).
Therefor, the 2 real roots of f(y) are: (1/3) and (-15/3 = - 5)
Answers: 1/3 and -5

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