How do you solve # (3y)/4 - y/3 = 10 #? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Shwetank Mauria Feb 18, 2016 Solution is #y=24# Explanation: To solve #(3y)/4−y/3=10#, multiply each term by LCM of denominators of all fractions. As these are 3 and 4, let us multiply by #12#. Equation then becomes #(3y)*12/4−y*12/3=10*12# or #9y-4y=120# i.e. #5y=120# i.e. #y=120/5=24# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1616 views around the world You can reuse this answer Creative Commons License