# How do you solve 4 - 2(v - 6)= - 8?

Jul 22, 2017

See a solution process below:

#### Explanation:

First, subtract $\textcolor{red}{4}$ from each side of the equation to isolate the term with parenthesis while keeping the equation balanced:

$- \textcolor{red}{4} + 4 - 2 \left(v - 6\right) = - \textcolor{red}{4} - 8$

$0 - 2 \left(v - 6\right) = - 12$

$- 2 \left(v - 6\right) = - 12$

Next, divide each side of the equation by $\textcolor{red}{- 2}$ to eliminate the need for parenthesis while keeping the equation balanced:

$\frac{- 2 \left(v - 6\right)}{\textcolor{red}{- 2}} = - \frac{12}{\textcolor{red}{- 2}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{- 2}}} \left(v - 6\right)}{\cancel{\textcolor{red}{- 2}}} = 6$

$v - 6 = 6$

Then, add $\textcolor{red}{6}$ to each side of the equation to solve for $v$ term while keeping the equation balanced:

$v - 6 + \textcolor{red}{6} = 6 + \textcolor{red}{6}$

$v - 0 = 12$

$v = 12$